What would the two VSEPR diagrams be? help please!?

This question needs to be more specific. On the face of it, the answer is simple; but then you wouldn't be asking. Dichloroethane is the compound and there are two isomers, 1,1 and 1,2. But in both of these there are no double bonds and no lone pairs on multivalent atoms. Chlorine has lone pairs but they don't enter into it since it's univalent. The electron pair repulsion situation is therefore the same in both, you have four bonds to each carbon and they act in the usual way going to the corners of a tetrahedron. Since Chlorine is larger than hydrogen and more electronegative it exerts slightly more repulsion than the hydrogens, widening the angle slightly. But only slightly.